When a conducting loop of resistance 10 Ω and area 10 cm2 is removed from an external magnetic field acting normally, the variation of induced current in the loop with time is shown in the figure.
Find the
(i) total charge passed through the loop. (ii) change in magnetic flux through the loop. (iii) magnitude of the magnetic field applied.
[2020 | Delhi | Section - C | SET - 1 SET - 2 SET - 3, Q.34 Q.32 Q.34]
Solution :
R = 10 Ω,
A=10 cm2
= 0.001 m2
i) Total charge passed through the loop (q)
q = area under the I-t graph
q = Area of Triangle
q = ½×0.4×1
= 0.2 C
ii) Change in magnetic flux=?
We know,
dΦ/dt = ε
dΦ/dt = IR
dΦ/dt = (dq/dt)R
dΦ = dq×R
dΦ = 0.2×10
dΦ = 2 Wb
iii) dΦ = Φ2-Φ1 = BACosθ
2 = B×0.001 cos0°
2 = B×0.001×1
2/0.001 = B
2000 = B
B = 2000 T
